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Let \alpha x+\beta y+y z=1 be the equation of a plane through the point (3,–2,5)and perpendicular to the line joning the points (1, 2, 3) and (–2, 3, 5). Then the value of \alpha \beta y is equal to :

Option: 1

6


Option: 2

__


Option: 3

__


Option: 4

__


Answers (1)

best_answer

Plane is perp. To the line joining the

(1,2,3) \&(-2,3,5)

So, line will be along normal of plane.

\vec{n}=(3,-1,-2) \text { or }(-3,1,2)

Compare it with eq. of plane, \alpha x+\beta y+r_2=1

\alpha=3, \beta=-1, r=-2 \text { or } \alpha=-3, \beta=1, r=2

So,\alpha \beta r=6

 

Posted by

Gunjita

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