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  • Let σ be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the electric fields in three different region  <img alt="E_{I}" src="https

Let σ be the uniform surface charge density of two infinite thin plane sheets shown in figure. Then the
electric fields in three different region  E_{I} , E_{II} and E_{III} are:

Option: 1

\vec{E}_I=\frac{2 \sigma}{\epsilon_0} \hat{n}, \vec{E}_{I I}=0, \vec{E}_{I I I}=\frac{2 \sigma}{\epsilon_0} \hat{n}


Option: 2

\vec{E}_I=\frac{ \sigma}{\epsilon_0} \hat{n}, \vec{E}_{I I}=0, \vec{E}_{I I I}=\frac{ \sigma}{2\epsilon_0} \hat{n}


Option: 3

\vec{E}_I=-\frac{ \sigma}{\epsilon_0} \hat{n}, \vec{E}_{I I}=0, \vec{E}_{I I I}=\frac{ \sigma}{\epsilon_0} \hat{n}


Option: 4

\vec{E}_I=0, \vec{E}_{I I}=\frac{\sigma}{\epsilon_0} \hat{n}, E_{I I I}=0


Answers (1)

best_answer

\begin{aligned} & \therefore E_I=-\frac{\sigma}{E_0} \hat{n} \\ & \therefore E_{I I}=0 \\ & \therefore E_{\text {III }}=-\frac{\sigma}{E_0} \hat{n} \end{aligned}

Posted by

himanshu.meshram

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