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  • Let f be a continuous function, whose range is a subset of  Q, the set of rational numbers. If <img a

Let f be a continuous function, whose range is a subset of  Q, the set of rational numbers. If \mathrm{f}(2)=1, then \mathrm{f}^{\prime}(3)

Option: 1

is 0


Option: 2

is 1


Option: 3

can not be found


Option: 4

none of these


Answers (1)

best_answer

f(x) has to be a constant function, otherwise range will contain infinitely many irrational numbers, which is not the case. Infact f(x)=1. Hence f^{\prime}(x)=0

\Rightarrow \mathrm{f}^{\prime}(3)=0

 

Posted by

Divya Prakash Singh

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