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Let R be a relation on N×N defined by (a, b)R(c, d) if and only if ad(b − c) = bc(a − d). Then R is

Option: 1

transitive but neither reflexive nor symmetric
 


Option: 2

 symmetric but neither reflexive nor transitive
 


Option: 3

 symmetric and transitive but not reflexive
 


Option: 4

reflexive and symmetric but not transitive


Answers (1)

best_answer

(a, b) R (c, d) ad(b – c) = bc(a – d)
For reflexive
(a, b) R (a, b)

\Rightarrow ab(b-a) \neq  ba(a – b)
R is not reflexive
For symmetric: 

(a,b) R(c,d) \Rightarrow ad(b –c) = bc (a –d)
then we check
(c, d) R (a, b) \Rightarrow cb(d – a) = ad(c – b)
                        \Rightarrow cb(a – d) = ad(b – c)
R is symmetric :

For transitive:
\because (2,3) R (3,2) and (3,2) R (5,30)
But (2,3) is not related to (5,30)
R is not transitive.

 

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jitender.kumar

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