Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Let , then all the points where <img alt="\mathrm{f(x)}" s

Let \mathrm{f(x)=|| x-1|-1|}, then all the points where \mathrm{f(x)} is not differentiable is (are)

Option: 1

1


Option: 2

1,2


Option: 3

\pm 1


Option: 4

0,1,2


Answers (1)

best_answer

\mathrm{f(x)=\left\{\begin{array}{lll}|x-1|-1 & \text { if } & |x-1| \geq 1 \\ 1-|x-1| & \text { if } & |x-1|<1\end{array}\right.}
          \mathrm{=\left\{\begin{array}{cc} -x & x \leq 0 \\ x & 0<x \leq 1 \\ 2-x & 1<x<2 \\ x-2 & x \geq 2 \end{array}\right.}

\mathrm{f} is not differentiable at 0,1,2 as these are corner points on the graph.

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 session 1 exam in the last week of January; registration details
anam-khan

Over 656 UPSC, JEE, NEET, other coaching aspirants refunded more than Rs 1 crore: Govt
anam-khan

NTA Exam Calendar 2025: JEE Main, NEET, CUET, UGC NET dates soon; websites to check

Latest Question