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  • Light wave traveling in air along -direction is given by <img alt="\mathrm{E}_{\mathrm{y}}=540 \operatorname{Sin} \pi \times 10^{4}(\mat

Light wave traveling in air along \mathrm{x}-direction is given by \mathrm{E}_{\mathrm{y}}=540 \operatorname{Sin} \pi \times 10^{4}(\mathrm{x}-c t) \mathrm{Vm}^{-1}. Then, the peak value of magnetic field of wave will be (Given \mathrm{c}=3 \times 10^{8} \mathrm{~ms}^{-1} )
 

Option: 1

\mathrm{18 \times 10^{-7} T}


Option: 2

\mathrm{54 \times 10^{-7} T}


Option: 3

\mathrm{54 \times 10^{-8} T}


Option: 4

18\times 10^{-8}\mathrm{T}


Answers (1)

best_answer

\mathrm{E_y =540 \sin \left(\pi \times 10^4(x-c t)\right) }

\mathrm{\frac{E_0}{B_0} =C }

\mathrm{B_0 =\frac{E_0}{C}=\frac{540}{3} \times 10^{-8} }

       \mathrm{=180 \times 10^{-8} }

\mathrm{B_0 =18 \times 10^{-7} \mathrm{~T}}

Hence (1) is correct option.
 

Posted by

Pankaj Sanodiya

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