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Magnetic flux (in weber) in a closed circuit of resistance 20 \Omega varies with time \mathrm{t(\mathrm{~s})} as \mathrm{\phi=8 \mathrm{t}^{2}-9 \mathrm{t}+5.}The magnitude of the induced current at \mathrm{\mathrm{t}=0.25 \mathrm{~s}} will be__________ \mathrm{mA}.

Option: 1

250


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{R =20 \Omega }

\mathrm{\phi =8 t^2-9 t+5 }

\mathrm{e =\left|\frac{d \phi}{d t}\right|=|16 t-9| }

\mathrm{a t \: \: t=0.25 \mathrm{~s}=\frac{1}{4} \mathrm{~s} }

\mathrm{ e =|4-9|=5 \mathrm{~V} \\ }

\mathrm{i =\frac{e}{k}=\frac{5}{20}=\frac{1}{4} \mathrm{~A} }

    \mathrm{i =0.25 \mathrm{~A}=250 \mathrm{~mA} }

The magnitude of the induced current at \mathrm{t=0.25 s} will be \mathrm{250 \mathrm{~mA}.}

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Nehul

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