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Match List I with List II

List I (Complex)

List II (Hybridization)
\mathrm{A. \: \mathrm{Ni}(\mathrm{CO})_{4}} \mathrm{ I.\ sp^{3}}
\mathrm{B. \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}} \mathrm{ II.\ \mathrm{sp}^{3} \mathrm{d}^{2} }
\mathrm{C. \left[\mathrm{Co}(\mathrm{CN})_{6}\right]^{3-}} \mathrm{ III. \ \mathrm{d}^{2} \mathrm{sp}^{3}}
\mathrm{ D. \left[\mathrm{CoF}_{6}\right]^{3-}} \mathrm{IV. \ dsp^{2}}

Choose the correct answer from the options given below :
 

Option: 1

A-IV, B-I, C-III, D-II


Option: 2

A-I, B-IV, C-III, D-II
 


Option: 3

A-I, B-IV, C-II, D-III

 


Option: 4

A-IV,B-I,C-II,D-III


Answers (1)

best_answer

From the list of hybridization -

\mathrm{Ni(CO)_{4}\quad Hybridization \, is\,\, sp^{3} }
\mathrm{\left [ Ni\left ( CN \right )_{4} \right ]^{2-}\quad Hybridization \, is\, \, dsp^{2} }
\mathrm{\left [ Co\left ( CN \right )_{6} \right ]^{3-}\quad Hybridization \, is\, \, d^{2}sp^{3} }
\mathrm{\left [ Co\left ( F_{6} \right ) \right ]^{3-}\quad Hybridization \, is\, \, sp^{3}d^{2} }        

Hence option (B) is correct.

Posted by

seema garhwal

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