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  • Match List - I with List - II, match the gas evolved during each reaction.

Match List - I with List - II, match the gas evolved during each reaction.

List - I

List - II
\mathrm{(A) \: \left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7} \stackrel{\Delta}{\longrightarrow}} \mathrm{(I)\: \mathrm{H}_{2}}
\mathrm{(B) \: \mathrm{KMnO}_{4}+\mathrm{HCl} \rightarrow} \mathrm{(II) \: \mathrm{N}_{2}}
\mathrm{(C) \: \mathrm{Al}+\mathrm{NaOH}+\mathrm{H}_{2} \mathrm{O} \rightarrow} \mathrm{(III) \: \mathrm{O}_{2}}
\mathrm{(D) \: \mathrm{NaNO}_{3} \stackrel{\Delta}{\longrightarrow}} \mathrm{(IV) \: \mathrm{Cl}_{2}}

Choose the correct answer from the options given below :
 

Option: 1

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})


Option: 2

(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{II})
 


Option: 3

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})
 


Option: 4

(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})


Answers (1)

best_answer

\mathrm{a) \, (NH_{4})_{2}Cr_{2}O_{7}\overset{\Delta }{\rightarrow}N_{2}+Cr_{2}O_{3}+4H_{2}O}
        Hence \mathrm{N_{2}} gas is evolved.

\mathrm{KMnO_{4}+HCl\rightarrow MnCl_{2}+KCl+Cl_{2}+H_{2}O}
         \mathrm{\rightarrow Cl_{2}} gas is evolved.

\mathrm{Al+NaOH+H_{2}O\rightarrow H_{2}+Na\left [ Al(OH)_{4} \right ]}
      \mathrm{\rightarrow H_{2}} gas is evolved

\mathrm{NaNO_{3}\rightarrow NaNO_{2}+O_{2}}
\mathrm{\rightarrow O_{2}} gas is evolved.

Hence option (C) is correct.

Posted by

SANGALDEEP SINGH

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