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Match List - I with List - II.

List - I

List - II

(Si-Compounds)

(Si-Polymeric/Other Products)

(A)\left(\mathrm{CH}_{3}\right)_{4} \mathrm{Si} \quad

(I) Chain Silicone

(B) \left(\mathrm{CH}_{3}\right) \mathrm{Si}(\mathrm{OH})_{3}

(II) Dimeric Silicone
(C)\left(\mathrm{CH}_{3}\right)_{2} \mathrm{Si}(\mathrm{OH})_{2} \quad

(III) Silane
(D)\left(\mathrm{CH}_{3}\right)_{3} \mathrm{Si}(\mathrm{OH}) \quad

(IV) 2D-Silicone

Choose the correct answer from the options given below :

Option: 1

(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})


Option: 2

(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{III})


Option: 3

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{III})


Option: 4

(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})


Answers (1)

best_answer

As we have learnt, 

(A) \left(\mathrm{CH}_{3}\right)_{4} \mathrm{Si} is called Silane (III)

(B) \left(\mathrm{CH}_{3}\right) \mathrm{Si}(\mathrm{OH})_{3} Polymerise to form 2D Silicone (IV)

(C) \left(\mathrm{CH}_{3}\right)_{2} \mathrm{Si}(\mathrm{OH})_{2} Polymerise to form chain Silicone (I)

(D) \left(\mathrm{CH}_{3}\right)_{3} \mathrm{Si}(\mathrm{OH}) Form dimeric silicone (II)

Hence, the correct answer is Option (4)

Posted by

Rishabh

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