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Match List - I with List - II.

List - I

List - II

(A) Spontaneous process

 (I) \mathrm{\Delta {H}<0}

(B) Process with\Delta \mathrm{P}=0, \Delta \mathrm{T}=0

 (II)\quad \Delta \mathrm{G}_{\mathrm{T}, \mathrm{P}}<0

(C) \mathrm\Delta {H} _ reaction

(III) Isothermal and isobaric process

(D) Exothermic Process

(IV) [Bond energies of molecules in reactants] -[Bond energies of product molecules]

Choose the correct answer from the options given below :

Option: 1

(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})


Option: 2

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{IV}),(\mathrm{D})-(\mathrm{I})


Option: 3

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{IV})


Option: 4

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{I}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})


Answers (1)

best_answer

\text { (A) For spontoneous process } \Rightarrow \mathrm{\Delta G_{T, p}<0(II)}

\text{(B) Process with } \mathrm{\Delta P=0} \rightarrow \text{Isobaric process}

                                     \mathrm{\Delta T}=0 \rightarrow \text{Isothermal process (III)}

\mathrm{(C)\; \Delta H_{\text {reaction }}}= \text{[Bond energies of molecules in reactents]}-\text{[Bond energies of product molecules] (IV)}

\mathrm{\text { (D) } \text {Exothermic process }, \Delta H<0\ (I)}

Hence, the correct answer is Option (2)

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