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Match List - I with List - II:

   List - I (Oxide)   

  List -II (Nature)        
\text { (A) } \mathrm{Cl}_{2} \mathrm{O}_{7}

 (I)   Amphoteric
\text { (B) } \mathrm{Na}_{2} \mathrm{O}

(II)  Basic      
\text { (C) } \mathrm{Al}_{2} \mathrm{O}_{3}

(III)  Neutral
\text { (D) } \mathrm{N}_{2} \mathrm{O}

(IV)  Acidic

Choose the correct answer from the options given below:

Option: 1

(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{II})


Option: 2

(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})


Option: 3

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{I})


Option: 4

(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})


Answers (1)

best_answer

The correct combination of the oxides and their nature is given below :

\begin{aligned} &\mathrm{Cl}_{2} \mathrm{O}_{7} \longrightarrow \text { Acidic } \\ \\&\mathrm{Na}_{2} \mathrm{O} \longrightarrow \text { Basic } \\ \\&\mathrm{Al}_{2} \mathrm{O}_{3} \longrightarrow \text { Amphoteric } \\ \\&\mathrm{N}_{2} \mathrm{O} \longrightarrow \text { neutral } \end{aligned}

Thus, the correct combination is 

Hence, Option (2) is correct.

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