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Match List - I with List - II.

List - I

(Compound)

List- II

(Shape)
(A) \mathrm{\mathrm{BrF}_{5}} (I) bent
(B)   \mathrm{\left[\mathrm{CrF}_{6}\right]^{3-}} (II) square pyramidal
(C)  \mathrm{\mathrm{O}_{3}} (III) trigonal bipyramidal
(D)  \mathrm{\mathrm{PCl}_{5}} (IV) octahedral

Choose the correct answer from the options given below:

Option: 1

(\mathrm{A})-(\mathrm{I}),(\mathrm{B})-(\mathrm{II}),(\mathrm{C})-(\mathrm{III}),(\mathrm{D})-(\mathrm{IV})


Option: 2

(\mathrm{A})-(\mathrm{IV}),(\mathrm{B})-(\mathrm{III}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})


Option: 3

(\mathrm{A})-(\mathrm{II}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{I}),(\mathrm{D})-(\mathrm{III})


Option: 4

(\mathrm{A})-(\mathrm{III}),(\mathrm{B})-(\mathrm{IV}),(\mathrm{C})-(\mathrm{II}),(\mathrm{D})-(\mathrm{I})


Answers (1)

\mathrm{(A)\; Steric \; Number=\frac{Valency+No.of \; Surrounding \; atoms-Charge}{2}}

1)\; \mathrm{BrF_{5} \; \; S.N=\frac{7+5}{2}=6\; \; \left [ 5\; bond\; Pair + 1\; lone \; pair \right ]}

                    Shape - Square Pyramidal

2) \mathrm{\left[\mathrm{CrF}_6\right]^{3-}S \cdot N=\frac{3+6+3}{2}=6 \quad[6 \text { bond pair }]}

                    Shape - Octahedral

3) \mathrm{O_3 \; \; \; S \cdot N=\frac{6+0}{2}=3 \quad[2\; bond \; Pair + 1 \; lone\; pair]}

                    Shape - bent

4) \mathrm{PCl}_5 \quad \mathrm{~S}.\mathrm{N}=\frac{5+5}{2}=5 \quad\left[\begin{array}{ll}5 \text{ bond pair}\end{array}\right]

                    Shape - Trigonal bipyromidal

\mathrm{A-II, B-I V, C-I, D-III}

Hence, the correct answer is Option (3).

Posted by

Sumit Saini

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