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Match List - I with List - II.

List-I List-II

(A) Lyophilic colloid

(I) Liquid-liquid colloid

(B) Emulsion

(II) Protective colloid

(C) Positively charged colloid

 (III)\mathrm{FeCl}_{3}+\mathrm{NaOH}

(D) Negatively charged colloid

(IV)\mathrm{FeCl}_{3}+ hot water

Choose the correct answer from the options given below :

Option: 1

\mathrm{({A})- (II), (B) - (I), (C) - (IV), (D) - (III)}


Option: 2

\mathrm{({A})- (III), (B) - (I), (C) - (IV), (D) - (II)}


Option: 3

\mathrm{({A})- (II), (B) - (I), (C) - (III), (D) - (IV)}


Option: 4

\mathrm{(A) - (III), (B) - (II), (C) - (I), (D) - (IV)}


Answers (1)

best_answer

(A) Lyophillic colloid \rightarrow Protective colloid (II)
(B) Emulsion \rightarrow liquid in liquid colloidal solutions (I)
(C) Positively charged colloid \rightarrow  If \mathrm{FeCl}_{3}  is added to the excess of hot water, a positively changed sol of ferric oxide is formed due to ad of \mathrm{Fe}^{3+} ions. (IV)

                    \mathrm{Fe}_{2} \mathrm{O}_{3} \cdot \mathrm{xH}_{2} \mathrm{O} |\mathrm{Fe}^{3+}

(D) Negatively charged colloid \rightarrow when ferric chloride is added to \mathrm{NaOH} solution a negatively charged sol is obtained with adsorption of \overline{\text{O}}\text{H} ions. (III)

                   \mathrm{Fe}_{2} \mathrm{O}_{3} \cdot \mathrm{xH}_{2} \mathrm{O} |\overline{\mathrm{O}}\text{H}

Hence, the correct answer is Option (1)

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