Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Mean and Standard deviation from the following observations of marks of 5 students of a tutorial group (marks out of 25), 8, 12, 13, 15, 22 are?Option:

Mean and Standard deviation from the following observations of marks of 5 students of a tutorial group (marks out of 25), 8, 12, 13, 15, 22 are?

Option: 1

14, 4.604
 


Option: 2

15, 4.604


Option: 3

14, 5.604

 


Option: 4

None


Answers (1)

best_answer

The correct option is a) 14, 4.604

The mean deviation and standard deviation are given below: 

\mathrm{\overline{X} = \frac{8+12+13+15+22}{5} = 14 }

\mathrm{\sum {\left ( X_{a}-\overline{X} \right )_{}}^{2} = 36+4+1+1+64 = 106 }

\mathrm{\sigma = \sqrt{\frac{(X_{i}-\overline{X})^{2}}{n}} = \sqrt{\frac{106}{5}} = 4.604 }

Hence option a) is the correct answer.

 

Posted by

HARSH KANKARIA

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Mains 2025 session 1 registration deadline on November 22; apply on jeemain.nta.nic.in
anam-khan

BTech Admission 2025 Live: JEE Mains, SRMJEEE, MET registrations underway; MHT CET syllabus updates
anam-khan

Centre issues coaching guidelines, prohibits centres from using false claims like '100% selection'

Latest Question