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Mean and Standard deviation from the following observations of marks of 5 students of a tutorial group (marks out of 25), 8, 12, 13, 15, 22 are?

Option: 1

14, 4.604
 


Option: 2

15, 4.604


Option: 3

14, 5.604

 


Option: 4

None


Answers (1)

best_answer

The correct option is a) 14, 4.604

The mean deviation and standard deviation are given below: 

\mathrm{\overline{X} = \frac{8+12+13+15+22}{5} = 14 }

\mathrm{\sum {\left ( X_{a}-\overline{X} \right )_{}}^{2} = 36+4+1+1+64 = 106 }

\mathrm{\sigma = \sqrt{\frac{(X_{i}-\overline{X})^{2}}{n}} = \sqrt{\frac{106}{5}} = 4.604 }

Hence option a) is the correct answer.

 

Posted by

HARSH KANKARIA

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