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Q

MHT-CET A flywheel at rest is to reach an angular velocity of 24 rev/s in 8 seconds with constant angular acceleration.

The total angle turned through during this interval is

  1. 48 rad

  2. 24 rad

  3. 96 rad

  4. 72 rad

Answers (2)
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3rd option is correct

\omega _{0}=0[initial]

\omega = 24 rad/s[final]

t=8sec

 \alpha = \frac{\omega }{t} = \frac{24}{8} = 3[angular acceleration]

\theta = \frac{1}{2} \alpha t^{2} = \frac{1}{2}\times 3 \times 8^{2} = 96 is the answer..!

Given

initial angular velocity,\omega _{0}=0

final angular velocity, \omega = 24 rad/s 

t = 8 seconds

angular acceleration, \alpha = \frac{\omega }{t} = \frac{24}{8} = 3

\theta = \frac{1}{2} \alpha t^{2} = \frac{1}{2}\times 3 \times 8^{2} = 96 

option (3) is correct

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