## Filters

Q&A - Ask Doubts and Get Answers
Q

# MHT-CET A flywheel at rest is to reach an angular velocity of 24 rev/s in 8 seconds with constant angular acceleration.

The total angle turned through during this interval is

Views

3rd option is correct

$\omega _{0}=0$[initial]

$\omega$ = 24 rad/s[final]

t=8sec

$\alpha = \frac{\omega }{t} = \frac{24}{8} = 3$[angular acceleration]

$\theta = \frac{1}{2} \alpha t^{2} = \frac{1}{2}\times 3 \times 8^{2} = 96$ is the answer..!

Given

initial angular velocity,$\omega _{0}=0$

final angular velocity, $\omega$ = 24 rad/s

t = 8 seconds

angular acceleration, $\alpha = \frac{\omega }{t} = \frac{24}{8} = 3$

$\theta = \frac{1}{2} \alpha t^{2} = \frac{1}{2}\times 3 \times 8^{2} = 96$

option (3) is correct

Exams
Articles
Questions