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  • MHT-CET A flywheel at rest is to reach an angular velocity of 24 rev/s in 8 seconds with constant angular acceleration.

The total angle turned through during this interval is

  1. 48 rad

  2. 24 rad

  3. 96 rad

  4. 72 rad

Answers (2)

Given

initial angular velocity,\omega _{0}=0

final angular velocity, \omega = 24 rad/s 

t = 8 seconds

angular acceleration, \alpha = \frac{\omega }{t} = \frac{24}{8} = 3

\theta = \frac{1}{2} \alpha t^{2} = \frac{1}{2}\times 3 \times 8^{2} = 96 

option (3) is correct

Posted by

Abhishek Sahu

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3rd option is correct

\omega _{0}=0[initial]

\omega = 24 rad/s[final]

t=8sec

 \alpha = \frac{\omega }{t} = \frac{24}{8} = 3[angular acceleration]

\theta = \frac{1}{2} \alpha t^{2} = \frac{1}{2}\times 3 \times 8^{2} = 96 is the answer..!

Posted by

akshaya

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