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What is the percentage mass of N in a mixture of 0.5 mole NH3 and 1 mole Ca(NO3)2?
A. 16.23
B. 12.17
C. 10.23
D. 20.28
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mass % of N in mixture =(total mass of N in mixture /total mass of mixture)*100
total mass of N in mixture =0.5 x 14 + 1x2x14=35.5
total mass of mixture = 172.5
mass % of N in mixture =(35.5/172.5)x100=20.57