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What is the percentage mass of N in a mixture of 0.5 mole NH3 and 1 mole Ca(NO3)2?

A. 16.23

B. 12.17

C. 10.23

D. 20.28

Answers (1)

mass % of N in mixture =(total mass of N in mixture /total mass of mixture)*100

total mass of N in mixture =0.5 x 14 + 1x2x14=35.5

total mass of mixture = 172.5

mass % of N in mixture =(35.5/172.5)x100=20.57

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