n is selected from the set {1,2,3......49} and the number 2n+3n+5n is formed. Total number of ways of selecting n so that the formed number is divisible by 4 is equal to
24
26
27
21
If n is odd
3n=4a+1, 5n -1 is divisible by 4 only when n is greater than or equal 2.
Now 4a+1+5n -1+2n is divisible by 4
Thus, n=3,5,7............49.
If n is even and greater than 2
3n=4a-1, 5n-1 is not divisible by 4.
The total number of ways of selecting n is 24.
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