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  • Need clarity, kindly explain! 3 g of activated charcoal was added to mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0. 042 N. The amount of acetic acid adsorbed (per gram of ch

3 g of activated charcoal was added to mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0. 042 N. The amount of acetic acid adsorbed (per gram of charcoal) is :

Option 1)

18 mg

 Option 2)

36 mg
Option 3)

42 mg

 Option 4)

54 mg

Answers (2)

best_answer

As we learnt in

Concept of limiting reagent and excess reagent -

The reactant which gets consumed and thus limits the amount of product formed is called the limiting reagent.

- wherein

 CH4 (g) + 2O2 (g) → CO2 (g) + 2 H2O (g) ;

In this reaction, if 1 mole of methane and 1 mole of oxygen are taken then oxygen would be limiting reagent.

 

 

 Number of equivalent adsorbed =50\times 0.06-50\times 0.042=0.9

Mass =\frac{0.9}{1000}\times 60\times 1000\ mg=54\ mg

Mass adsorbed per gm =\frac{54}{3}=18\ mg


Option 1)

18 mg

Option 2)

36 mg

Option 3)

42 mg

Option 4)

54 mg

Posted by

perimeter

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