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A charged oil drop is suspended in a uniform field of 3 x 104 V/m so that it neither falls nor rises. The charge on the drop will be (take the mass of the charge = 9.9 × 10-15 kg and g = 10 m/s2)

Option 1)

3.3 × 10-18 C

Option 2)

3.2 × 10-18 C

Option 3)

1.6 × 10-18 C

Option 4)

4.8 × 10-18 C

Answers (1)

best_answer

As we learnt in

Dual Nature of Radiation -

Wave -particle duality postulates that all particles exhibit both wave and particle properties

-

 

 At equilibrium: 

Net force = 0 

mg - qE = 0  \Rightarrow\ \;q=\frac{mg}{E}

q=\frac{9.9\times{10^{-15}\times10}}{3\times10^{4}}=3.3\times10^{-18}\ C

Correct answer is 1

 

 


Option 1)

3.3 × 10-18 C

This is the correct option.

Option 2)

3.2 × 10-18 C

This is an incorrect option.

Option 3)

1.6 × 10-18 C

This is an incorrect option.

Option 4)

4.8 × 10-18 C

This is an incorrect option.

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