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Engineering
1 week, 3 days ago

Need clarity, kindly explain! A person throws two fair dice. He wins Rs. 15 for throwing a doublet( same numbers on the two dice), wins Rs. 12 when the throw resultsin the sum of 9 , and loses Rs. 6 for any other outcome on the throw.Then the expecte

A person throws two fair dice. He wins Rs. 15 for throwing a doublet 

( same numbers on the two dice), wins Rs. 12 when the throw results

in the sum of 9 , and loses Rs. 6 for any other outcome on the throw. 

Then the expected gain / loss (in Rs.) of the person is :

  • Option 1)

    \frac{1}{2}  gain 

  • Option 2)

    \frac{1}{4} loss

  • Option 3)

    \frac{1}{2} loss

  • Option 4)

    2 gain

 
Answers (1)
Views
P Plabita
Answered 1 week, 3 days ago

When 2 dice are thrown , Sample space would be

 \begin{Bmatrix} (1,1) &(2,1) ........... &(6,1) \\ (1,2) & (2,2) ...........&(6,2) \\ (1,3)& (2,3) ........... & (6,3)\\ (1,4)& .................. &(6,4) \\ (1,5)& ................... &(6,5) \\ (1,6) & ................... & (6,6) \end{Bmatrix}

Now, the expected gain or loss = both + Sum (9) - other 

                                                 =(\frac{6}{36}\times 15)+(\frac{4}{36}\times 12)-(\frac{26}{36}\times 6)=-\frac{1}{2}

                                        So, there is loss of Rs \: \: \frac{1}{2}

 

 


Option 1)

\frac{1}{2}  gain 

Option 2)

\frac{1}{4} loss

Option 3)

\frac{1}{2} loss

Option 4)

2 gain

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