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A rigid close container contains an ideal gas at 27oC temperature and 2 atm pressure , if temperature raised to 127oC then find the final pressure of gas

  • Option 1)

    2 atm

  • Option 2)

    1.66 atm

  • Option 3)

    2.66 atm

  • Option 4)

    1 atm

 

Answers (1)

As we learnt in 

Gay Lussac’s Law -

Pressure -Temperature Relationship

- wherein

\frac{P_{1}}{T_{1}}= \frac{P_{2}}{T_{2}}

 

 

According to Gay Lussac's law P\: \alpha\: T

\frac{P_{1}}{P_{2}}= \frac{T_{1}}{T_{2}}

P_{1}= 2\: atm\\* T_{1}= 27+273= 300\: k\\*T_{2}= 127+273= 400\: k \\*P_{2}= ?

\frac{2}{P_{2}}= \frac{300}{400}

P_{2}= \frac{800}{300}= 2.66\: atm


Option 1)

2 atm

Incorrect

Option 2)

1.66 atm

Incorrect

Option 3)

2.66 atm

Correct

Option 4)

1 atm

Incorrect

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