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  2. Need clarity, kindly explain! - Current Electricity - JEE Main-3
# Engineering

The resistance of a galvanometer is 50\:ohm and the maximum current which can be passed through it is 0.002\:A  . What resistance must be connected to it in order to convert it into an ammeter of range 0-0.5\:A ?

  • Option 1)

    0.5\:\:ohm

  • Option 2)

    0.002\:\:ohm

  • Option 3)

    0.02\:\:ohm

  • Option 4)

    0.2\:\:ohm

 

Answers (1)
S solutionqc

For converting galvanometer into ammeter we must add a short resistance 

I_{g}=\frac{I\:S}{G+S}

Given,

I_{g}=0.002\:A

I=0.5\:A

G=50\: \Omega

\Rightarrow0.002=\frac{0.5\:S}{50+S} \approx \frac{S}{100}

\Rightarrow S=0.2\:\Omega


Option 1)

0.5\:\:ohm

Option 2)

0.002\:\:ohm

Option 3)

0.02\:\:ohm

Option 4)

0.2\:\:ohm

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