A common emitter amplifier circuit, built using an npn transistor, is shwon in the figure. Its dc current gain is 250, R_{C}=1 k\Omega and V_{CC}=10 V. what is the minimum base current for V_{CE} to reach saturation?

  • Option 1)

    40\mu A

  • Option 2)

    100\mu A

  • Option 3)

    7\mu A

  • Option 4)

    10\mu A

Answers (1)

During saturation

V_{CE}=0

i_{c}=\frac{V_{CC}}{R_{C}}=\frac{10}{10^{3}}=250

Current gain= \beta =\frac{i_{c}}{i_{B}}=250

i_{B}=\frac{i_{c}}{250}=\frac{10 \times 10^{-3}}{250}=40 \mu A


Option 1)

40\mu A

Option 2)

100\mu A

Option 3)

7\mu A

Option 4)

10\mu A

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