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  • Need clarity, kindly explain! - Electrostatics - JEE Main

A fully charged capacitor has a capacitance C .It is discharged through a small coil of resistance wire embedded in a thermally insulated block of specific heat capacity s and mass m. If the temperature of the block is raised by \Delta T,the potential difference V cross the capacitance is

 

  • Option 1)

    \frac{ms\Delta T}{C}

  • Option 2)

    \sqrt{\frac{2ms\Delta T}{C}}

  • Option 3)

    \sqrt{\frac{2mC\Delta T}{s}}

  • Option 4)

    \frac{mC\Delta T}{s}

 

Answers (2)

As we learnt in

Energy Stored -

U=\frac{1}{2}CV^{2}=\frac{1}{2}QV=\frac{Q^{2}}{2C}

-

 

 Energy of capacitor = Heat energy of block

\frac{1}{2}CV^{2}= ms\Delta T

or\: \: \: \: V= \sqrt{\frac{2ms\Delta T}{C}}


Option 1)

\frac{ms\Delta T}{C}

Incorrect

Option 2)

\sqrt{\frac{2ms\Delta T}{C}}

Correct

Option 3)

\sqrt{\frac{2mC\Delta T}{s}}

Incorrect

Option 4)

\frac{mC\Delta T}{s}

Incorrect

Posted by

Sabhrant Ambastha

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