Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Need clarity, kindly explain! H+, He+ and O++ ions having same kinetic energy pass through a region of space filled with uniform magnetic field B directed perpendicular to the velocity of ions. The masses of the ions H+, He+ and O++ are respectively

H+, He+ and O++ ions having same kinetic energy pass through a region of space filled with uniform magnetic field B directed perpendicular to the velocity of ions. The masses of the ions H+, He+ and O++ are respectively in the ratio 1:4:16. As a result

  • Option 1)

    H+ ions will be deflected most
     

  • Option 2)

    O++ ions will be deflected least


     

  • Option 3)

    He+ and O++ ions will suffer same deflection

     

  • Option 4)

    All ions will suffer the same deflection

 

Answers (1)

best_answer

As we learnt in 

Radius of charged particle -

r=\frac{mv}{qB}=\frac{P}{qB}=\frac{\sqrt{}2mk}{qB}=\frac{1}{B}\sqrt{}\frac{2mV}{q}

-

 

Deflection \propto \frac{1}{r} \propto\frac{q}{\sqrt m}

\because r =\frac{\sqrt{2mE}}{qB}

Ratio of deflection: \frac{1}{1}:\frac{1}{\sqrt{4}}:\frac{2}{\sqrt{16}}=1:\frac{1}{2}:\frac{1}{2}

 

Therefore deflection is same for He+ and O++ .


Option 1)

H+ ions will be deflected most
 

incorrect

Option 2)

O++ ions will be deflected least


 

incorrect

Option 3)

He+ and O++ ions will suffer same deflection

 

correct

Option 4)

All ions will suffer the same deflection

incorrect

Posted by

prateek

View full answer

Similar Questions

Trending Articles/News

anam-khan

BITSAT 2024 application correction facility begins tomorrow; editable fields
anam-khan

BITSAT 2024 registration window closes tomorrow; exam from May 20
anam-khan

BITSAT 2024 registration deadline extended till April 16; session 1 exam from May 19 to 24

Latest Question