If 

  • Option 1)

    divisible by x but not y

  • Option 2)

    divisible by y but not x

  • Option 3)

    divisible by neither x nor  y

  • Option 4)

    divisible by both x and   y

 

Answers (2)

As we learnt in 

Property of determinant -

If each element in a row ( or column ) of a determinant is written as the sum of two or more terms then the determinant can be written as the sum of two or more determinants

- wherein

 

 D=\begin{vmatrix} 1& 1&1\\ 1 & 1+x &1\\ 1&1 &1+y \end{vmatrix}

=1\left ( 1+x+y+xy-1 \right )-1\left ( 1+y-1 \right )+1\left ( 1-1-x \right )= xy

= x + y + xy - y - x

= xy 

which is divisible by both x and y


Option 1)

divisible by x but not y

Incorrect Option

 

Option 2)

divisible by y but not x

Incorrect Option

 

Option 3)

divisible by neither x nor  y

Incorrect Option

 

Option 4)

divisible by both x and   y

Correct Option

 

N neha

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