# In which of the following molecules/ions are all the bonds not equal? Option 1) $SF_{4}$ Option 2) $SiF_{4}$ Option 3) $XeF_{4}$ Option 4) $BF{_{4}}^{-}$

As we learnt in

Shape of molecules -

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in SF4  Hybridisation is spd and shape is see saw but all bonds are not equal. Length of Axial bond is longer than equitarial bond.

In siF4, xeF4 and $BF_{4}^{-}$ all bonds are equal.

$SF_{4}$     molecule show $sp^{3}d$ hybridisation but its expected trigonal bipyramidal geometry gets distorted due to presence of a lone pair of electrons and it becomes distorted tetrahedral or see­saw with the bond angles equal to $89^{\circ}$ and $177^{\circ}$ instead of the expected angles of $90^{\circ}$ and $180^{\circ}$ respectively.

$SiF_{4}$:    $sp^{3}d^{2}$ hybridisation, and tetrahedral geometry.

$XeF_{4}:sp^{3}d^{2}$shape is square planar instead of octahedral due to presence of two lone pair of electrons on $Xe$ atom.

$BF{_{4}}^{-}:sp^{3}$ hybridisation and tetrahedral geometry

Option 1)

$SF_{4}$

This option is correct

Option 2)

$SiF_{4}$

This option is incorrect

Option 3)

$XeF_{4}$

This option is incorrect

Option 4)

$BF{_{4}}^{-}$

This option is incorrect

N

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