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  • Need clarity, kindly explain! In which of the following molecules/ions are all the bonds not equal?

In which of the following molecules/ions are all the bonds not equal?

  • Option 1)

    SF_{4}

  • Option 2)

    SiF_{4}

  • Option 3)

    XeF_{4}

  • Option 4)

    BF{_{4}}^{-}

 

Answers (2)

best_answer

As we learnt in 

Shape of molecules -

-

 

 in SF4  Hybridisation is sp3 d and shape is see saw but all bonds are not equal. Length of Axial bond is longer than equitarial bond. 

In siF4, xeF4 and BF_{4}^{-} all bonds are equal.

SF_{4}     molecule show sp^{3}d hybridisation but its expected trigonal bipyramidal geometry gets distorted due to presence of a lone pair of electrons and it becomes distorted tetrahedral or see­saw with the bond angles equal to 89^{\circ} and 177^{\circ} instead of the expected angles of 90^{\circ} and 180^{\circ} respectively.

SiF_{4}:    sp^{3}d^{2} hybridisation, and tetrahedral geometry.

 

XeF_{4}:sp^{3}d^{2}shape is square planar instead of octahedral due to presence of two lone pair of electrons on Xe atom.

BF{_{4}}^{-}:sp^{3} hybridisation and tetrahedral geometry


Option 1)

SF_{4}

This option is correct

Option 2)

SiF_{4}

This option is incorrect

Option 3)

XeF_{4}

This option is incorrect

Option 4)

BF{_{4}}^{-}

This option is incorrect

Posted by

divya.saini

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