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The velocity of a projectile at the initial point A is (2\hat{i}+3\hat{j}) m/s. It's velocity (in m/s) at point B is:

 

  • Option 1)

    2\hat{i}+3\hat{j}

  • Option 2)

    -2\hat{i}-3\hat{j}

  • Option 3)

    -2\hat{i}+3\hat{j}

  • Option 4)

    2\hat{i}-3\hat{j}

 

Answers (1)

best_answer

Fig (7358)

From Fig x component remains unchanged, while the y component is Reverse, so velocity at pt. B will be 

(2\hat{i}-3\hat{j}) \:\:m/s.


Option 1)

2\hat{i}+3\hat{j}

This solution is incorrect.

Option 2)

-2\hat{i}-3\hat{j}

This solution is incorrect.

Option 3)

-2\hat{i}+3\hat{j}

This solution is incorrect.

Option 4)

2\hat{i}-3\hat{j}

This solution is correct.

Posted by

prateek

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