Larger number of oxidation states are exhibited by the actinoids than those by the lanthanoids, the main reason being Option 1) More reactive nature of the actinoids than the lanthanoids Option 2) $4f$ orbitals more diffused than the $5f$ orbitals Option 3) Lesser energy difference between $5f$ and $6d$ than between $4f$ and $5d$  orbitals Option 4) More energy difference between $5f$ and $6d$ than between $4f$ and $5d$  orbitals

V Vakul

As we learnt in

Oxidation states -

The common oxidation state of lanthanoid is +3 low occasionally +2  and  +4  ions in solution or in the solid compound are also obtained.

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and

Oxidation states -

Ac shows +3 oxidation state generally but some Ac. Also, stable till +7 oxidation states.

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Actinoids exhibits more number of oxidation state in general than the Lanthanoids. This is because of lesser energy difference between 5f and 6d than between 4f and 5d orbitals.

Option 1)

More reactive nature of the actinoids than the lanthanoids

This option is incorrect

Option 2)

$4f$ orbitals more diffused than the $5f$ orbitals

This option is incorrect

Option 3)

Lesser energy difference between $5f$ and $6d$ than between $4f$ and $5d$  orbitals

This option is correct

Option 4)

More energy difference between $5f$ and $6d$ than between $4f$ and $5d$  orbitals

This option is incorrect

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