Find the tension T_2 for the system shown in fig:

  • Option 1)

    1 N

  • Option 2)

    2 N

  • Option 3)

    5 N

  • Option 4)

    4 N

 

Answers (1)

As we learnt in 

3 block connected with string -

- wherein

a=\frac{F}{m_{1}+m_{2}+m_{3}}


T_{1}=\frac{(m_{2}+m_{3})F}{m_{1}+m_{2}+m_{3}}


T_{2}=\frac{m_{3}F}{m_{1}+m_{2}+m_{3}}

 T_{3}=3Kg

T_{2}=2Kg+T_{3}=2Kg+3Kg

T_{2}=5Kg = T_{2}= 5\times g= 5N

 

 

 

 

 

 

 

 

 

 

 

 

 


Option 1)

1 N

This option is incorrect.

Option 2)

2 N

This option is incorrect.

Option 3)

5 N

This option is correct.

Option 4)

4 N

This option is incorrect.

Preparation Products

Knockout BITSAT 2020

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 1999/-
Buy Now
Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout BITSAT-JEE Main 2021

An exhaustive E-learning program for the complete preparation of JEE Main and Bitsat.

₹ 27999/- ₹ 16999/-
Buy Now
Knockout BITSAT-JEE Main 2020

An exhaustive E-learning program for the complete preparation of JEE Main and Bitsat.

₹ 14999/- ₹ 7999/-
Buy Now
Exams
Articles
Questions