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  • Need clarity, kindly explain! - Oscillations and Waves - JEE Main-9

A source of sound emits 400\pi W power which is uniformly distributed over a sphere of 10 m radius. What is the loudness of sound on the surface of sphere

  • Option 1)

    20dB

  • Option 2)

    200\pi \;dB

  • Option 3)

    120dB

  • Option 4)

    120\pi\;dB

 

Answers (1)

best_answer

Intensity = \frac{power}{area} \Rightarrow I = \frac{P}{A}

I = \frac{400\pi}{4\pi X 10^{-2}} = 1 watt/m^{2}

L = 10 log_{10} \frac{I}{I_{o}} = 120 dB

 

Intensity of periodic sound waves -

I= \frac{\Delta P{_{m}}^{2}}{2\rho v}
 

- wherein

\Delta P_{m}= Maxmium pressure change

\rho = density

v= velocity of sound

 

 

 


Option 1)

20dB

This is incorrect.

Option 2)

200\pi \;dB

This is incorrect.

Option 3)

120dB

This is correct.

Option 4)

120\pi\;dB

This is incorrect.

Posted by

Avinash

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