# If $'M'$ is the mass of water that rises in a capillary tube of radius $'r'$, then mass of water which will rise in a capillary tube of radius $'2r'$ is : Option 1)   $M$ Option 2)   $\frac{M}{2}$ Option 3) $4M$ Option 4) $2\: M$

$m=\rho \: Ah$

$m=\left ( \rho \right )\left ( \pi r^{2} \right )\frac{\left ( 2Tcos\theta \right )}{\rho gr}$

$m\; \propto r$

$\frac{m_{1}}{m_{2}}=\frac{r_{1}}{r_{2}}$

$\frac{M}{m_{2}}=\frac{r}{2r}$

$M_{2}=2M$

Option 1)

$M$

Option 2)

$\frac{M}{2}$

Option 3)

$4M$

Option 4)

$2\: M$

Exams
Articles
Questions