If 'M' is the mass of water that rises in a capillary tube of radius 'r', then mass of water which will rise in a capillary tube of radius '2r' is :

 

  • Option 1)

      M

  • Option 2)

      \frac{M}{2}

  • Option 3)

    4M

  • Option 4)

    2\: M

 

Answers (1)

m=\rho \: Ah

m=\left ( \rho \right )\left ( \pi r^{2} \right )\frac{\left ( 2Tcos\theta \right )}{\rho gr}

     m\; \propto r

\frac{m_{1}}{m_{2}}=\frac{r_{1}}{r_{2}}

\frac{M}{m_{2}}=\frac{r}{2r}

M_{2}=2M

 

 


Option 1)

  M

Option 2)

  \frac{M}{2}

Option 3)

4M

Option 4)

2\: M

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