The torque acting is 2000 Nm with an angular acceleration of 2 rad/s^{2}. The moment of inertia of body is

  • Option 1)

    1200 kg m^{2}

  • Option 2)

    900 kg m^{2}

  • Option 3)

    1000 kg m^{2}

  • Option 4)

    Can't say

 

Answers (1)
V Vakul

As we learnt in 

Analogue of second law of motion for pure rotation -

\vec{\tau }=I\, \alpha

- wherein

Torque equation can be applied only about two point

(i) centre of motion.

(ii) point which has zero velocity/acceleration.

 

 T = I\alpha

2000 = I\times 2 \Rightarrow I=1000 Kg.m^{2}

 


Option 1)

1200 kg m^{2}

Incorrect

Option 2)

900 kg m^{2}

Incorrect

Option 3)

1000 kg m^{2}

correct

Option 4)

Can't say

Incorrect

Preparation Products

Knockout BITSAT 2021

It is an exhaustive preparation module made exclusively for cracking BITSAT..

₹ 4999/- ₹ 2999/-
Buy Now
Knockout BITSAT-JEE Main 2021

An exhaustive E-learning program for the complete preparation of JEE Main and Bitsat.

₹ 27999/- ₹ 16999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
 
Exams
Articles
Questions