Get Answers to all your Questions

header-bg qa

The energy required to remove the electron from a singly ionized Helium atom is 2.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is :

  • Option 1)

    20 eV

  • Option 2)

    34 eV

  • Option 3)

    79 eV

  • Option 4)

    109 eV

 

Answers (2)

best_answer

As we learned

 

Energy of electron in nth orbit -

E= -\left ( \frac{me^{4}}{8\epsilon _{0}^{2}h^{2}} \right )\frac{z^{2}}{n^{2}}

 

- wherein

E\alpha \frac{z^{2}}{n^{2}} \\\frac{me^{4}}{8\epsilon_{0}^{2}h^{2}}= 13.6ev

 

 The energy required to remove an electron from singly Ionise Helium atom 

E+E_{0}\cdot \frac{z^{2}}{n^{2}}=(13.6ev)\cdot 2^{2}=54.4ev

energy required to remove electron from helium atom = \frac{54.4}{2.2}=24.73ev

Total energy required = 54.4+24.7\simeq 79eV

 

 


Option 1)

20 eV

Option 2)

34 eV

Option 3)

79 eV

Option 4)

109 eV

Posted by

Aadil

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE