Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Need clarity, kindly explain! - Three Dimensional Geometry - JEE Main-3

Distance between two parallel planes 2x+y+2z=8\; and\; 4x+2y+4z+5=0\; is

  • Option 1)

    7/2

  • Option 2)

    5/2

  • Option 3)

    3/2

  • Option 4)

    9/2

 

Answers (1)

best_answer

As we learnt in 

Distance of a point from plane (Cartesian form) -

The length of perpendicular from P(x_{1},y_{1},z_{1}) to the plane

ax+by+cz+d= 0 is given by  \frac{\left [ ax_{1}+by_{1} +cz_{1}+d\right ]}{\left | \sqrt{a^{2}+b^{2}+c^{2}} \right |}

 

-

 

 4x+2y+4z=16

4x+2y+4z=-5

d= \frac{\left | 6-(-5) \right |}{\sqrt{4^{2}+4^{2}+2^{2}}}= \frac{21}{6}= \frac{7}{2}

 


Option 1)

7/2

Correct option 

Option 2)

5/2

Incorrect option

Option 3)

3/2

Incorrect option

Option 4)

9/2

Incorrect option

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 session 1 exam in the last week of January; registration details
anam-khan

Over 656 UPSC, JEE, NEET, other coaching aspirants refunded more than Rs 1 crore: Govt
anam-khan

NTA Exam Calendar 2025: JEE Main, NEET, CUET, UGC NET dates soon; websites to check

Latest Question