When forces F1 ,F2 ,F3 are acting on a particle of mass  m such that F2 and F are mutually perpendicular, then the particle remains stationary If the force F1 is now removed then the acceleration of the particle is :

  • Option 1)

    F1/ m

  • Option 2)

    F2F /mF1

  • Option 3)

    (F2 - F3) / m

  • Option 4)

    F2 / m

 

Answers (1)

As we learnt in

Impulse Momentum Theorem -

\vec{F}=\frac{d\vec{p}}{dt}

\int_{t_{1}}^{t_{2}}\vec{F}dt=\int_{p_{1}}^{p_{2}}\vec{dp}

- wherein

If \bigtriangleup t  is increased, average force is decreased

 

 

 

:  F2 and F3  have a resultant equivalent to F1

\therefore  Aceleration = F1/m  .

Correct option is 1.


Option 1)

F1/ m

This is the correct option.

Option 2)

F2F /mF1

This is an incorrect option.

Option 3)

(F2 - F3) / m

This is an incorrect option.

Option 4)

F2 / m

This is an incorrect option.

Preparation Products

JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Knockout JEE Main April 2021 (Subscription)

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 4999/-
Buy Now
Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Knockout JEE Main January 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Exams
Articles
Questions