Browse by Stream
Discuss Doubts
Home
Search for Exam, Articles, Questions
get app
Go To Your Study Dashboard
  1. Home
  2. Need explanation for: A particle is projected from a height along horizontal direction with a speed 5 m/s. Then its speed after 1.2 sec is ? (g = 10 m/s2)
# Engineering

A particle is projected from a height along horizontal direction with a speed 5 m/s. Then its speed after 1.2 sec is ? (g = 10 m/s2)

  • Option 1)

    15 m/s

  • Option 2)

    12 m/s

  • Option 3)

    13 m/s

  • Option 4)

    14 m/s

 

Answers (1)
A Aadil Khan

As we have learnt,

 

Projectile Projected Horizontally -

V=\sqrt{u^{2}+g^{2}t^{2}}


 

- wherein

V= velocity of Projectile at an instant

u= initial velocity of projection

 

 

v = \sqrt{u^2 + g^2 t^2} = \sqrt{5^2 + (1.2\times 10)^2} = \sqrt{169} = 13 m/s


Option 1)

15 m/s

Option 2)

12 m/s

Option 3)

13 m/s

Option 4)

14 m/s

Similar Questions

Exams
Articles
Questions