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  • Need explanation for: A particle is projected from a height along horizontal direction with a speed 5 m/s. Then its speed after 1.2 sec is ? (g = 10 m/s2)

A particle is projected from a height along horizontal direction with a speed 5 m/s. Then its speed after 1.2 sec is ? (g = 10 m/s2)

  • Option 1)

    15 m/s

  • Option 2)

    12 m/s

  • Option 3)

    13 m/s

  • Option 4)

    14 m/s

 

Answers (1)

best_answer

As we have learnt,

 

Projectile Projected Horizontally -

V=\sqrt{u^{2}+g^{2}t^{2}}


 

- wherein

V= velocity of Projectile at an instant

u= initial velocity of projection

 

 

v = \sqrt{u^2 + g^2 t^2} = \sqrt{5^2 + (1.2\times 10)^2} = \sqrt{169} = 13 m/s


Option 1)

15 m/s

Option 2)

12 m/s

Option 3)

13 m/s

Option 4)

14 m/s

Posted by

Aadil

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