# A particle is projected from a height along horizontal direction with a speed 5 m/s. Then its speed after 1.2 sec is ? (g = 10 m/s2) Option 1) 15 m/s Option 2) 12 m/s Option 3) 13 m/s Option 4) 14 m/s

As we have learnt,

Projectile Projected Horizontally -

$V=\sqrt{u^{2}+g^{2}t^{2}}$

- wherein

$V=$ velocity of Projectile at an instant

$u=$ initial velocity of projection

$v = \sqrt{u^2 + g^2 t^2} = \sqrt{5^2 + (1.2\times 10)^2} = \sqrt{169} = 13 m/s$

Option 1)

15 m/s

Option 2)

12 m/s

Option 3)

13 m/s

Option 4)

14 m/s

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