A particle of charge q and mass m moves in a circular orbit of radius r with angular speed ω. The ratio of the magnitude of its magnetic moment to that of its angular momentum depends on

 

  • Option 1)

    ω and q

     

  • Option 2)

    ω, q and m

     

  • Option 3)

    q and m

     

  • Option 4)

    ω and m

     

 

Answers (1)
V Vakul

As we learnt in 

Magnetic moment (M) -

M=NiA

- wherein

N-number of turns in the coil 

i-current throughout the coil 

A-area of the coil 

 

Magnetic moment =I.A.=\frac{q}{T}.A

 =\frac{q\omega}{2\pi}. \pi r^2=\frac{1}{2}q\omega r^2

angular momentum =mr^{2}\omega

\therefore \frac{magnetic \ moment}{Angular \ momentum}=\frac{\frac{1}{2}q \omega r^{2}}{mr^{2}\omega}=\frac{q}{2m}


Option 1)

ω and q

 

incorrect

Option 2)

ω, q and m

 

incorrect

Option 3)

q and m

 

correct

Option 4)

ω and m

 

incorrect

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