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  • Need explanation for: A particle of mass 200 grams executes SHM. The restoring force is provided by a spring of force constant 80 N/m. The time period of oscillation is

A particle of mass 200 grams executes SHM. The restoring force is provided by a spring of force constant 80 N/m. The time period of oscillation is

  • Option 1)

    0.31 s

  • Option 2)

    0.15 s

  • Option 3)

    0.05 s

  • Option 4)

    0.02 s

 

Answers (1)

T = 2\pi\sqrt{\frac{m}{k}} = 2\pi\sqrt{\frac{0.2}{0.8}} = 0.31s

 

Time period of oscillation for spring mass system -

T= 2\pi \sqrt{\frac{m}{K}}

- wherein

m = mass of block

K = spring constant

 

 

 


Option 1)

0.31 s

This is correct.

Option 2)

0.15 s

This is incorrect.

Option 3)

0.05 s

This is incorrect.

Option 4)

0.02 s

This is incorrect.

Posted by

subam

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