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- Need explanation for: Cerium ( Z = 58 ) s an important member of the lanthanoids. Which of the following statements about cerium is incorrect?
Cerium ( Z = 58 ) s an important member of the lanthanoids. Which of the following statements about cerium is incorrect?
- Option 1)
The common oxidation states of cerium are +3 and +4.
- Option 2)
The +3 oxidation state of cerium is more stable than +4 oxidation state.
- Option 3)
The +4 oxidation state of cerium is not known in solutions.
- Option 4)
Cerium (IV) acts as an oxidising agent.
Answers (2)
As we learnt in
Oxidation states -
The common oxidation state of lanthanoid is +3 low occasionally +2 and +4 ions in solution or in the solid compound are also obtained.
-
i) Common oxidation state of Ce is +3 and +4.
ii) +3 oxidation state is more stable than +4 for Ce.
iii) Ce(IV) acts as an oxidising agent.
Option 1)
The common oxidation states of cerium are +3 and +4.
This option is incorrect.
Option 2)
The +3 oxidation state of cerium is more stable than +4 oxidation state.
This option is incorrect.
Option 3)
The +4 oxidation state of cerium is not known in solutions.
This option is correct.
Option 4)
Cerium (IV) acts as an oxidising agent.
This option is incorrect.
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