Cerium ( Z = 58 ) s an important member of the lanthanoids. Which of the following statements about cerium is incorrect?

  • Option 1)

    The common oxidation states of cerium are +3 and +4.

  • Option 2)

    The +3 oxidation state of cerium is more stable than +4 oxidation state.

  • Option 3)

    The +4 oxidation state of cerium is not known in solutions.

  • Option 4)

    Cerium (IV) acts as an oxidising agent.

 

Answers (2)

As we learnt in

Oxidation states -

The common oxidation state of lanthanoid is +3 low occasionally +2  and  +4 ions in solution or in the solid compound are also obtained.

-

i) Common oxidation state of Ce is +3 and +4.

ii) +3 oxidation state is more stable than +4 for Ce.

iii) Ce(IV) acts as an oxidising agent.


Option 1)

The common oxidation states of cerium are +3 and +4.

This option is incorrect.

Option 2)

The +3 oxidation state of cerium is more stable than +4 oxidation state.

This option is incorrect.

Option 3)

The +4 oxidation state of cerium is not known in solutions.

This option is correct.

Option 4)

Cerium (IV) acts as an oxidising agent.

This option is incorrect.

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