Get Answers to all your Questions

header-bg qa

A ray of light along x+\sqrt{3}y=\sqrt{3} gets reflected upon reaching x-axis ,the equation of the reflected ray is :

  • Option 1)

    \sqrt{3}y=x-1

  • Option 2)

    y=x+\sqrt{3}

  • Option 3)

    \sqrt{3}y=x-\sqrt{3}

  • Option 4)

    y=\sqrt{3}x-\sqrt{3}

 

Answers (2)

best_answer

As we learnt in

Slope – point from of a straight line -

y-y_{1}=m(x-x_{1})

- wherein

m\rightarrow slope

\left ( x_{1},y_{1} \right )\rightarrow point through which line passes

y=\frac{-x}{\sqrt{3}}+1

Put y=0,\:x=\sqrt{3}

So, \frac{y}{x-\sqrt{3}}=\frac{1}{\sqrt{3}}

\sqrt{3}y-x-\sqrt{3}=0

 

 


Option 1)

\sqrt{3}y=x-1

This option is incorrect.

Option 2)

y=x+\sqrt{3}

This option is incorrect.

Option 3)

\sqrt{3}y=x-\sqrt{3}

This option is correct.

Option 4)

y=\sqrt{3}x-\sqrt{3}

This option is incorrect.

Posted by

Plabita

View full answer

Crack JEE Main with "AI Coach"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
jee_ads