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  • Need explanation for: - Co-ordination Compounds - JEE Main

Amongst Ni(CO)_4, [Ni(CN)_4].. and .. [NiCl_4]^{2-} 

  • Option 1)

    Ni(CO)_4 and [Ni(Cl)_4]^{2-}are  diamagnetic  and [Ni(CN)_4]^{2-}is paramagnetic

  • Option 2)

    [Ni(Cl)_4]^{2-}  and [Ni(CN)_4]^{2-} are diamagnetic andNi(CO)_4 is paramagnetic

  • Option 3)

    Ni(CO)_4 and [Ni(CN)_4]^{2-}are diamagnetic and [Ni(Cl)_4]^{2-} is paramagnetic

  • Option 4)

    Ni(CO)_4 is diamagnetic and[Ni(Cl)_4]^{2-} and  [Ni(CN)_4]^{2-} are paramagnetic

 

Answers (1)

As we have learned

Magnetic Moments (spin only) -

\sqrt{n\left ( n+2 \right )} where n= number of unpaired electron.

- wherein

Number of unpaired e^{-} s and corresponding magnetic moments

1\rightarrow 1.7\\2\rightarrow 2.8\\3\rightarrow 3.9\\4\rightarrow 4.9\\5\rightarrow 5.9

 

 

The electronic configuration of Ni in

              [Ni(CN)_{4}]^{2-}, [Ni(Cl_4)^{2-}]and[Ni(CO)_{4}] are as following

 

CO and CN^{-} are strong ligands so they induces pairing of electrons so their complexes are diamagnetic while Cl^{-} is a weak ligand so it does not induce the pairing of electrons so its complex is paramagnetic.

 

 

 

 


Option 1)

Ni(CO)_4 and [Ni(Cl)_4]^{2-}are  diamagnetic  and [Ni(CN)_4]^{2-}is paramagnetic

Option 2)

[Ni(Cl)_4]^{2-}  and [Ni(CN)_4]^{2-} are diamagnetic andNi(CO)_4 is paramagnetic

Option 3)

Ni(CO)_4 and [Ni(CN)_4]^{2-}are diamagnetic and [Ni(Cl)_4]^{2-} is paramagnetic

Option 4)

Ni(CO)_4 is diamagnetic and[Ni(Cl)_4]^{2-} and  [Ni(CN)_4]^{2-} are paramagnetic

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Vakul

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