Browse by Stream
Discuss Doubts
Home
Search for Exam, Articles, Questions
get app
Go To Your Study Dashboard
  1. Home
  2. Need explanation for: - Communication Systems - JEE Main
# Engineering

In a line of sight radio communication a distance of about 50km is kept between the transmitting and receiving antennas. If the height of the receiving antennas 70 m, then the minimum height of the transmitting antenna should be: 

(Radius of the Earth= 6.4 \times 10^{6 }m)

  • Option 1)

    20 m

  • Option 2)

    51 m

  • Option 3)

    32 m

  • Option 4)

    40 m

 

Answers (1)
S solutionqc

R=6.4 \times 10^{6}

d=Range=50km

d=\sqrt{2Rh_{T}}+\sqrt{2Rh_{R}}

\Rightarrow 50 \times 10^{3}=\sqrt{2 \times 64 \times 10^{5} h_{T}}+\sqrt{2 \times 64 \times 10^{5} h_{R}}

\Rightarrow h_{T}=32m


Option 1)

20 m

Option 2)

51 m

Option 3)

32 m

Option 4)

40 m

Similar Questions

Preparation Products

Knockout JEE Main April 2021

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 22999/- ₹ 14999/-
Buy Now
Knockout JEE Main April 2022

An exhaustive E-learning program for the complete preparation of JEE Main..

₹ 34999/- ₹ 24999/-
Buy Now
Test Series JEE Main April 2021

Take chapter-wise, subject-wise and Complete syllabus mock tests and get in depth analysis of your test..

₹ 6999/- ₹ 4999/-
Buy Now
JEE Main Rank Booster 2021

This course will help student to be better prepared and study in the right direction for JEE Main..

₹ 13999/- ₹ 9999/-
Buy Now
Test Series JEE Main April 2022

Take chapter-wise, subject-wise and Complete syllabus mock tests and get an in-depth analysis of your test..

₹ 6999/-
Buy Now
Boost your Preparation for JEE Main 2021 with Personlized Coaching
Start Now
 
Exams
Articles
Questions