Browse by Stream
Discuss Doubts
Home
Search for Exam, Articles, Questions
get app
Go To Your Study Dashboard
  1. Home
  2. Need explanation for: - Communication Systems - JEE Main
# Engineering

In a line of sight radio communication a distance of about 50km is kept between the transmitting and receiving antennas. If the height of the receiving antennas 70 m, then the minimum height of the transmitting antenna should be: 

(Radius of the Earth= 6.4 \times 10^{6 }m)

  • Option 1)

    20 m

  • Option 2)

    51 m

  • Option 3)

    32 m

  • Option 4)

    40 m

 

Answers (1)
S solutionqc

R=6.4 \times 10^{6}

d=Range=50km

d=\sqrt{2Rh_{T}}+\sqrt{2Rh_{R}}

\Rightarrow 50 \times 10^{3}=\sqrt{2 \times 64 \times 10^{5} h_{T}}+\sqrt{2 \times 64 \times 10^{5} h_{R}}

\Rightarrow h_{T}=32m


Option 1)

20 m

Option 2)

51 m

Option 3)

32 m

Option 4)

40 m

Similar Questions

Exams
Articles
Questions