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  • Need explanation for: - Dual Nature of Matter and Radiation - JEE Main

 de-Broglie wavelength of an electron accelerated by a voltage of 50 V is close to

(\left | e \right |=1.6\times 10^{-19}C,\: m_{e}=9.1\times 10^{-31}kg,\: h=6.6\times 10^{-34}Js)

Option 1)

0.5\dot{A}

 Option 2)

1.2\dot{A}
Option 3)

1.7\dot{A}

 Option 4)

2.4\dot{A}

Answers (1)

best_answer

As we learnt in

De - Broglie wavelength -

\lambda = \frac{h}{p}= \frac{h}{mv}= \frac{h}{\sqrt{2mE}}

- wherein

h= plank's\: constant

m= mass \: of\: particle

v= speed \: of\: the \: particle

E= Kinetic \: energy \: of \: particle

 

 {\lambda}=\frac{h}{p}=\frac{h}{\sqrt{2m.(K.E.)}}=\frac{h}{\sqrt{2m(eV)}}

    =\frac{6.6\times10^{-34}}{\sqrt{2\times 9.1\times 10^{-31}\times{1.6}{\times10^{-19}{\times}50}}}m=1.7\AA

Correct option is 3.


Option 1)

0.5\dot{A}

This is incorrect option.

Option 2)

1.2\dot{A}

This is incorrect option.

Option 3)

1.7\dot{A}

This is the correct option.

Option 4)

2.4\dot{A}

This is incorrect option.

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