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  • Need explanation for: - Given the equilibrium constant : of the reaction : is 10 X1015calculate theof this reaction at - Equilibrium - JEE Main

Given the equilibrium constant :

K_{c} of the reaction :

Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s) is 10 X1015 calculate the E_{cell}^{\varnothing } of this reaction at 298 K

\left [ 2.303\frac{RT}{F}at\: 298 K=0.059 V \right ]

  • Option 1)

    0.4736 mV

  • Option 2)

    0.04736 V

  • Option 3)

    0.4736 V

  • Option 4)

    0.04736 mV

Answers (1)

best_answer

 

Equilibrium constant and Enthalpy Change -

The equilibrium constant for an endothermic reaction ( positive \bigtriangleup H ) increases as the temperature increases.

-

 

 

The equilibrium constant for the reverse reaction -

The equilibrium constant for the reverse reaction is the inverse of the equilibrium constant for the reaction in the forward direction.

- wherein

K'_{c}=\frac{1}{K_{c}}

{K'_{c}}   is  equilibrium constant for reverse direction.

E_{cell}^{0}=\frac{0.0591}{N}log\: k_{c}=\frac{0.0591}{2}log(1\times 10^{16})=0.4728 V

 


Option 1)

0.4736 mV

Option 2)

0.04736 V

Option 3)

0.4736 V

Option 4)

0.04736 mV

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