In the compound Fe0.85O , the percent of iron existing as Fe (III) is
25.3%
30.3%
35.3%
40.3%
For every 1 mol of oxygen atom, 0.85 mol of iron atoms is present. If r is the amount of Fe(III) present, them the electrical neutrality requires that
This gives
Ppercent of Fe(III)= %
Metal deficiency defect -
This defect is arise when cation with lower oxidation state are replaced by cation with higher oxidation state, but crystal is electrically neutral.
- wherein
Ex :
Option 1)
25.3%
This is incorrect
Option 2)
30.3%
This is incorrect
Option 3)
35.3%
This is correct
Option 4)
40.3%
This is incorrect
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