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One end of a uniform wire of length L and of weight W is attached rigidly to a point on the roof and a weight W1 is suspended from its lower end. If S is the area of cross-section of the wire, the stress in the wire at a height 3L/4 from its lower end is,

  • Option 1)

    \frac{W_{1}}{S}

  • Option 2)

    \left ( W_{1} +\frac{W}{4}\right )S

  • Option 3)

    \left ( W_{1} +\frac{3W}{4}\right )S

  • Option 4)

    \frac{W_{1}+W}{S}

 

Answers (1)

best_answer

As discussed in

Stress -

The internal restoring force per unit area of deformed body.

- wherein

Due to the forces, the body gets deformed and internal forces appear.

 

As discussed in @14070 

Total force and height 3L/4 from its lower end = weight suspended + weight of 3/4 of the chain

= W_{1}+\left ( \frac{3W}{4} \right )


Option 1)

\frac{W_{1}}{S}

This solution is incorrect.

Option 2)

\left ( W_{1} +\frac{W}{4}\right )S

This solution is incorrect.

Option 3)

\left ( W_{1} +\frac{3W}{4}\right )S

This solution is correct.

Option 4)

\frac{W_{1}+W}{S}

This solution is incorrect.

Posted by

prateek

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