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  • Need explanation for: - Oscillations and Waves - JEE Main-3

Two equations of two SHM are y =a\sin (\omega t - \alpha) and y =b\cos (\omega t - \alpha). The phase difference between the two is 

  • Option 1)

    0\degree

  • Option 2)

    \alpha\degree

  • Option 3)

    90\degree

  • Option 4)

    180\degree

 

Answers (1)

best_answer

y = a\sin(\omega t -\alpha) = a\cos(\omega t -\alpha -\frac{\pi}{2})

Another equation given is y = b\cos(\omega t -\alpha)

So, there exist a phase difference of \frac{\pi}{2} = 90\degree 

 

Phase constant -

The constant \delta appearing in eqation x=A\sin \left ( wt+\delta \right ) is called phase constant. It describes initial state.

 

- wherein

This constant depends on the choice of the instant t=0.

 

 

 


Option 1)

0\degree

This is incorrect.

Option 2)

\alpha\degree

This is incorrect.

Option 3)

90\degree

This is correct.

Option 4)

180\degree

This is incorrect.

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Plabita

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